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0.03x^2-126x+9010=0
a = 0.03; b = -126; c = +9010;
Δ = b2-4ac
Δ = -1262-4·0.03·9010
Δ = 14794.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-126)-\sqrt{14794.8}}{2*0.03}=\frac{126-\sqrt{14794.8}}{0.06} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-126)+\sqrt{14794.8}}{2*0.03}=\frac{126+\sqrt{14794.8}}{0.06} $
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